Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicXy = 3 (1) xy = 28 (2) From (1) x= y3 Put that in (2) to get y(y3) = 28, or y^2 3y = 28, or y^2 3y 28 = 0, or (y7)(y4) = 0 Hence y = 7 or 4, Then the corresponding values of x are 4 or 7 Therefore (x^2y^2) = (4)^2(7)^2 = 1649 = 65 Answer = 65
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(x y)^3-(x-y)^3-6y(x^2-y^2)-Polynomial Identities When we have a sum (difference) of two or three numbers to power of 2 or 3 and we need to remove the brackets we use polynomial identities (short multiplication formulas) (x y) 2 = x 2 2xy y 2 (x y) 2 = x 2 2xy y 2 Example 1 If x = 10, y = 5a (10 5a) 2 = 10 2 2·10·5a (5a) 2 = 100 100a 25a 2Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
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Question Consider The Function F(x, Y) = {x^3y Xy^3/x^2 Y^2 If (x, Y) Not Equal To (0, 0) 0 If (x, Y) = (0, 0) Compute The Partial Derivatives F_x (0, 0) And Fu(0, 0) Take Care Here, We Are Relegated To Using The Analytical Limit Definition Of The Partials Because The Function IsThe given equation is (x y) 3 − (x − y) 3 − 6y (x 2 − y 2) = ky 2 Recall the formula `a^3 b^3 = (ab) (a^2 ab b^2)`X^3 x^2 y x y^2 y^3 Extended Keyboard;
Answer to Find dy/dx for the equation at the given point x = y^3 6y^2 9;Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreFind an answer to your question Prove that (x y)^3 (x y) ^3 6y (x^2 y^2) =8y^3 fshaik51fshaik51 Math Secondary School Prove that (x y)^3 (x y) ^3 6y (x^2 y^2) =8y^3
Watch Video in App This browser does not support the video element 348 k 17 k Answer Step by step solution by experts to helpClick here👆to get an answer to your question ️ If (x y)^3 (x y)^3 6y(x^2 y^2) = ky^2 , then k = Take x = X l;
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Y = Y m (l and m are constants) So, dy/dx = dY/dX Therefore, the equation becomes (in X, Y) If l, m are chosen to satisfy In X, Y the equation is homogeneous and of the first degree Put Y = VX Then Separating the variables (X, V) and integrating, where A is an arbitrary constant(4, 1) By signing up, you'll get thousands of stepbystep prove that x y 3 x y 3 6y x2 y2 8y3 Mathematics TopperLearningcom 7736 Topperlearning CBSE Class 9 Ask The Expert Answered
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y=2x The tangent is a straight line so it will be of the form y=mxc We can get m by finding the 1st derivative dy/dx as this is the gradient of the line We can then get c, the intercept, by using the values of x and y which are given To find the 1st derivative we can use implicit differentiation x^2xyy^2=3 D(x^2xyy^2)=D(3) Using The Product Rule and The Chain rule3x 2 3y 2 = 3 • (x 2 y 2) Trying to factor as a Difference of Squares 92 Factoring x 2 y 2 Check x 2 is the square of x 1 Check y 2 is the square of y 1 Factorization is (x y) • (x y) Canceling Out 93 Cancel out (x y) which appears on both sides of the fraction line Final result 3 • (x y)Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
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Graph y=x^23 y = x2 − 3 y = x 2 3 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 3 x 2 3 Tap for more steps Use the form a x 2 b x c a x 2 b xIf (x y)^3 (x y^3 6y (x^2 Prove that (XY)^3 (XY)^36Y (X^2Y^2)=8Y^3
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Calculadoras gratuitas paso por paso para álgebra, Trigonometría y cálculoX 2 y 2 − 1 = x 2 / 3 y , which can easily be solved for y y = 1 2 ( x 2 / 3 ± x 4 / 3 4 ( 1 − x 2)) Now plot this, taking both branches of the square root into account You might have to numerically solve the equation x 4 / 3 4 ( 1 − x 2) = 0 in order to get the exact x interval Share answered Dec 22 '12 at 1731 ChristianIf x^2y^2= and xy=40then find the value of x^3y^3 If x^ (2)y^ (2)= and xy=40,then find the value of x^ (3)y^ (3) Please scroll down to see the correct answer and solution guide
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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicSimplifying 3(x 2) = y 6 Reorder the terms 3(2 x) = y 6 (2 * 3 x * 3) = y 6 (6 3x) = y 6 Reorder the terms 6 3x = 6 y Solving 6 3x = 6 y Solving for variable 'x' Move all terms containing x to the left, all other terms to the right Add '6' to each side of the equation 6 6 3x = 6 6 y Combine like (xy)^3 (xy)^3 6y(x^2y^2) Share with your friends Share 0 D e a r S t u d e n t G i v e n (x y) 3 (xy) 3 6 y (x 2 y 2) = (x y) 3
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X 2 y 2 4x 2 y 3x 2 = x 2 • (y 2 4y 3) Step 6 Pulling out like terms 61 Pull out like factors y 3 5y 2 = y 2 • (y 5) Trying to factor by splitting the middle term 62 Factoring y 2 4y 3 The first term is, y 2 its coefficient is 1 The middle term is, 4y its coefficient is 4 The last term, "the constant", is 3 Explanation x2 4x y2 −6y − 3 = 0 or x2 4x 4 y2 −6y 9 = 4 9 3 or (x 2)2 (y −3)2 = 42 The centerradius form of the circle equation is (x– h)2 (y– k)2 = r2, with the center being at the point (h,k) or ( − 2,3) and the radius being r = 4 So, center is at ( − 2,3) and radius is 4 unit graph {x^24xy^26 y3 Stepbystep explanationtex {(x y)}^{3} {(x y)}^{3} 6y( {x}^{2} {y}^{2} )/textex {x}^{3} {y}^{3} {x}^{3} {y}^{3} 6y {x}^{
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kash EduTech Pvt Ltd What are you looking for? Which of the following demonstrates how to factor x^2y^2?Do the grouping x 2 − 2 x y 3 x − 6 y = (x 2 − 2 x y) (3 x − 6 y), and factor out x in the first and 3 in the second group x\left(x2y\right)3\left(x2y\right) x ( x − 2 y ) 3 ( x − 2 y )
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(xy)(xy) = x^2 y^2 2xy but x^2 y^2 = 10 and xy = 3 (xy)(xy) = 10 2*3 (xy)(xy) = 10 6 (xy)(xy) = 4 Hope this helpsInt (x^2 y^2 x y^3) dx dy, x = 2 to 2, y = 2 to 2 Extended Keyboard;If xy = 3, and xy = 28, what will be the value of (x^2y^2)?
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Find stepbystep Calculus solutions and your answer to the following textbook question Let f(x, y) = {x^3y xy^3/x^2y^2 if (x, y) ≠ (0, 0) , 0 if (x, y) = (0, 0Click here👆to get an answer to your question ️ Verify x^3 y^3 = (x y)(x^2 xy y^2) using some non zero positive integers and check by actual multiplication Can you call theses as identities?If x 2 x 1 is a factor of ax 3 bx 2 cx d, then the real root of ax 3 bx 2 cx d = 0 is If x 2r occurs x (2 / x 2) n, then n 2r must be of the form If x m y n = (x y) mn, then (dy/dx) x = 1, y =2 is equal to If x y = y x, then x(xy log x) dy/dx is equal to If xe xy = y sin 2 x, then at x = 0, dy / dx = If Xy E2 X Y
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Ex 25, 9 Verify (i) x3 y3 = (x y) (x2 – xy y2) Ex 25, 9 Verify (ii) x3 y3 = (x y) (x2 xy y2) LHS x3 y3 We know (x y)3 = x3 y3 3xy (x y How do you find #dy/dx# by implicit differentiation of #(xy)^3=x^3y^3# and evaluate at point (1,1)? The polynomial `5x^(5) 3x^(3) 2x^(2) k` gives a remainder 1, when divided by `x 1` Find the value of k asked in Algebraic Expressions by Lohith01 ( 970k points)
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Transcribed Image Textfrom this Question f (x, y) = y^3 3x^2y 6x^2 6y^2 2 f (x, y) = 2x^4 2x^2 y^2 f (x, y) = x^3 12xy 8y^3 f (x, y) = Xy 1/x 1/y f {x, y) = xe^2x^22y^2 f (x, y) = e^4yx^2y^2 Find the local maximum and minimum values and saddle point (s) of the function If you have threedimensional graphing softwareCheck to see if f y is equal to N f y = −x 2g0(y) = 6y −x2 3 so that g0(y) = 6y2 3 That gives g(y) = 2y3 3y Put this back in to get the full solution, f(x,y) = c x3 −x2y 2x2y3 3y = C 3 Problem 4 (2xy2 2y)(2x2y 2x)dy dx = 0 Check for "exactness"Click here👆to get an answer to your question ️ Simplify (x y)^3 (x y)^3 6y(x^2 y^2)
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2(xy) (xy)(xy) (xy)(xy) (xy)^2 Answers 3 Get Other questions on the subject Mathematics Mathematics, 1430, gagem1278 What is the volume of a rectangular prism if the length is 104 mm the width is 5 mm in the height is 8 mmGet an answer for 'What is the limit of `(x^3y^3)/(x^2y^2)` as (x,y)>(0,0)?Calculus Basic Differentiation Rules Implicit Differentiation
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Solve 2xy/ X Y = 3/2 Xy/ 2x Y = 3/10 X Y ≠ 0 and 2x Y ≠ 0 CISCE ICSE Class 9 Question Papers 10 Textbook Solutions Important Solutions 5 Question Bank Solutions Concept Notes & Videos 258 Syllabus Advertisement Remove all ads Solve 2xy/ X Y = 3/2 Xy/ 2x Y = 3/10 X Y ≠ 0 and 2x Y ≠ 0Add 3 3 to both sides of the equation x2 y2 4x−6y = 3 x 2 y 2 4 x 6 y = 3 Complete the square for x2 4x x 2 4 x Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 1, b = 4, c = 0 a = 1, b যদি (xy)^(3)(xy)^(3)6y(x^(2)y^(2))=ky^(2) , তারপরে কে = Updated On 23 To keep watching this video solution for FREE, Download our App Join the 2 Crores Student community now!
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